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Milwaukee named drunkest city in America

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A bartender prepares a beer in a bar. REUTERS/Daniel Munoz
A bartender prepares a beer in a bar. REUTERS/Daniel Munoz

UNDATED (WSAU) – A new list has named Milwaukee the drunkest city in America.

"The Daily Beast" looked at average alcohol consumption, binge drinking and deaths from alcoholic liver disease to compile its list of the 40 Drunkest Cities.

In Milwaukee, each person drinks an average of about 13 drinks a month. Seven percent of Milwaukeeans are heavy drinkers.

Fargo, North Dakota was the second drunkest city. The Daily Beat ranked San Francisco third, Austin Texas fourth and Reno, Nevada fifth.

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